First, we need to know the probability of each combination:

A) 0.45 x 0.45 x 0.55 = 0.13613 = 13.61%

B) 0.45 x 0.55 x 0.45 = 0.13613 = 13.61%

C) 0.55 x 0.45 x 0.45 = 0.13613 = 13.61%

Then, the probability of two males in the next three new born is:

0.1361 + 0.1361 + 0.1361 = 0.4083 = 40.83%