Statistics and Probability for Business Management 1100
Solutions to Midterm 1
-
- (ii) number of siblings is discrete quantitative
- (i) favorite color is qualitative
- Her class of 70 Business Statistics students constitute the sample;
all Pitt students constitute the population
-
- 2 would be the only reasonable mean; the others are too low or too
high
- 1.5 is the only reasonable standard deviation; .2 is already too
small, and 5.5 is too large (sketch roughly what a histogram would look like)
- shape would be skewed right because of a few students with relatively
many siblings; on the left side, it can't go any lower than zero
-
- Five Number Summary values are 1st (16), 7th (25), average of 13th and
14th (26), 20th (29), and 26th (33)
- Q1+1.5(IR)=29+1.5(4)=35; no values are larger than this, so there are
no high outliers
- Omitting 16 would increase the mean (not averaging in that small value)
and decrease the standard deviation (omitting outlier reduces spread)
-
- (ii) boxplot for IQs of private school students would have a higher
center because there'd be fewer IQs at the low end
- (i) public school IQ boxplot would have more spread, taking into account
some students with very low IQs
- (ii) both shapes should be reasonably symmetric, no reason to expect
otherwise
-
- .9909
- 1.28
-
- mean plus or minus 2 standard deviations produces the interval from
20.6 to 25
- z=(24-22.8)/1.1 = 1.09; the proportion less than 1.09 is .8821, so
the proportion greater is .1379, or about 14 percent
- smallest 3 percent correspond to z=-1.88, so x=22.8-1.88(1.1)=20.732
-
- (iii) positive because people with higher incomes would buy more
expensive homes
- (iii) strong because r is close to 1
- 24+2.5(50)=149
- 151-149=2 thousand dollars
- (i) r should decrease because the cluster would be looser
- (iii) 100 is outside the range of income values used to produce the
regression line
- b=2.5
-
- females:180/200 is higher than 480/600
- females: 100/300 is higher than 10/100
- (ii) rate of admission is higher for business school, and percentage
of males applying is higher; note that males have a higher percentage of
admissions in the combined table (490/700 higher than 280/500) so we have
an example of Simpson's Paradox
- (iii) non-response is the worst problem for mailed-out questionaires
like this
- (a) structured (although I realized that I forgot to include zero as
a possiblity, so I accepted (d) one-sided)
- (a) matched pairs
-
- 10 in the overlap, 30 remaining in C but not G, 20 remaining in G but
not C, 40 outside the circles
- First column 10 then 20, second column 30 then 40
- 20/100=.2
- 60/100=.6
-
- P(E)=P((W and E) or (not W and E))=.85(.95)+.15(.92)=.8075+.1380=.9455
- .8075/.9455=.8540
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